Forum Moderators: open
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<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="content-type" content="text/html; charset=utf-8"/>
<title>Google AJAX Search API Sample</title>
<script src="http://www.google.com/jsapi?key=ABQIAAAA1XbMiDxx_BTCY2_F................"></script>
<script type="text/javascript">
/*
* How to use the Feed Control to grab, parse and display feeds.
*/
google.load("feeds", "1");
function OnLoad() {
// Create a feed control
var feedControl = new google.feeds.FeedControl();
// Add two feeds.
feedControl.addFeed("http://news.google.com/news?pz=1&ned=us&hl=en&q=jobs&output=rss", "Google");
feedControl.addFeed("http://rss.cnn.com/rss/money_latest.rss", "CNN");
// Draw it.
feedControl.draw(document.getElementById("content"));
}
google.setOnLoadCallback(OnLoad);
</script>
</head>
<body style="font-family: Arial;border: 0 none;">
<div id="content">Loading...</div>
</body>
</html>
That code appears to be from the Google AJAX Search API Developer's Guide [code.google.com]. You would want to read through their documentation to get a better idea of the elements that can be manipulated.
If you'd like another way to get feeds on your site we have a classic post: Short guide to include RSS on your website [webmasterworld.com] that uses Magpie to do much the same.
