Forum Moderators: bakedjake
My version gets passed a directory name as a parameter. It then outputs a line for each sub-directory, showing the directory name (excluding the portion passed as a parameter), along with the number of files (tracks) within the directory.
Hopefully someone will find it useful. Many thanks to jjc_mn for providing the starting point.
#!/bin/bash
#counts files in subdirectories
#set -x
top_dir=$1
if [ -z $top_dir ]
then
echo "Directory path must be given"
exit -1
fi
if [ ! -d $top_dir ]
then
echo "Directory path given is not valid"
exit -2
fi
echo "Analysing files in $top_dir..."
date_stamp=`date +"%m%d%Y.%H%M%S"`
temp_file="temp.$date_stamp.txt"
done_loop=""
find $top_dir -type d ¦ sort > $temp_file
exec 3< $temp_file
until [ $done_loop ]
do
read <&3 myline
if [ $? != 0 ]
then
done_loop=1
continue
fi
dir_count=`find "$myline/." \( -name . -o -prune \) -type f ¦wc -l`
if [ $dir_count != 0 ]
then
short_name=${myline:${#top_dir}}
short_name=${short_name#/}
short_name=${short_name:=$top_dir}
count_desc="tracks"
if [ $dir_count = 1 ]
then
count_desc="track"
fi
echo "$short_name ($dir_count $count_desc)"
fi
done
rm $temp_file
#EOF
or to exclude from the search hidden dirs/files:
find . -type f ¦ awk '!/\/\..*/ {dir=gensub(/(.+\/).+/,"\\1","g",$0); dir_list[dir]++} END {for (d in dir_list) printf "%s %s\n",d,dir_list[d]}' ¦ sort
awk '{
# $0 will contain relative path to the file
# we don't care about file name, so will strip it
# for details on gensub check awk man page
# so, variable "dir" will hold the directory name
dir=gensub(/(.+\/).+/,"\\1","g",$0);
# add directory name to the hash "dir_list"
# at the same time increase the counter by one
# for that directory name
dir_list[dir]++
END {
# read the hash and print values
# "d" will be directory name
# hash element "dir_list[d]" will be a number
# showing how many files are in that directory
for (d in dir_list)
printf "%s %s\n",d,dir_list[d]
}'
"sort" will sort output :)
Extra part in second line (one to exclude hidden files) says:
!/\/\..*/
what means: anything what has slash with following dot in a path consider as a hidden file/dir and ignore.
Thanks you for welcoming us :)
that is really sweet stuff!
i haven't used awk enough recently.
and i never thought about using find -type f that way.
i've always wondered what the ls option was to include the path and now i know...
=8)
Thanks you for welcoming us
And thank you for breaking it down.
that is really sweet stuff!
Indeed. I'm always impressed by the power of the command line in the hand's of an artist.
Maxchk, I've gotta agree with Coopster - amazing what can be achieved at the command line, in the right hands! And thanks for breaking it down for the rest of us.
gensub(/(.+\/).+/,"\\1","g");
I learned something new today! Thanks.
